u 40: Chon D

Des66

O. u 40: Chon D

Do de bai cho 4 phirong trlnh => Tuong (mg v&i 4 an so: 2 an la s6 mot cua saccarozo va 2 an la hi~u suat thiiy phan ciia 2 chat Ta dijt s6 mo! cua saccarozo, mantozo fan I uot la a va b mol. B~t hi~u suat phan ll'tlg thuy phan Ian hrot Ia x va y,

Ta c6: mx

=

ffisaccarozO" + mmantozO"

= 342a + 342b = 136,8 gam (1)

+

)Phan frng thuy phan :

1 Saccarozo -+ 1 Glucoza

+

1 Fructozo:

axmol

{2x+v} 13a 6 x a

Ilu

0,1---..-- (x-l-y)

..- ~~~- ~~~·~-..:. ... _~ "-:i...:::,~---L ","':'""'.."• ---~-~--~~ .•_ .~r----~~~ "•_•

!Y" k'A raa (2 )

tneu ien: x ~ a ~ 6 :;:;; ^x+ y Tac6:

(

a - x

= ~::)

a - x

=

0,1

Zx+y-x x+y a=03

13 => fa '

T-x

_--::)--X=^0,45 ^13a ₀₄₅

^lx ⁼

^0,2

Zx + y - x x

+

y 6 ' (thoa man dieu ki~n)

(2x+y) x

(x+y)

+) X + 0,5 mol HCI: nco2

=

x + y

=

^0,15

=> y = O,l(mol).

+)Y + HCI:

Bao toan nguyen

to

Cl, ta c6

the

^{coi Y}

+ HCI la MCl(X)va Iuong HCI ban dau tham gia phan 11'Ilg:

MCI + AgN03 -+ AgCl + MN03 -

z - z

HCI + AgN03 - AgCt + HN03

0,5 -+ 0,5

Suy ra z

+

0,5

=

0,52 => z

=

0,02 (mol).

mx = 0,1(2M

+

60) + 0,05. (M + 61) + 0,02. (M + 3,5)

= 20,29::) M = 39(K).

CA.u 37: Chon D

Ta c6: dipeptit + 2HCI

+

H20 - hon hep mufii

Mol x-+ Zx -+ x

Suy ra: 16 + 18x + 73x

=

25,1 => x

=

O,l(mol).

Mpeptit = 160 ::) X la: Ala -Ala.

H2NCH(CH3)CO - NHCH(CH3)COOH Suy ra Y la H[NH - CH(CH3) - CO]s OH

- 15C02 + 13,5H20 + 2,SN2

Sau phan 11'Ilg thu duqc: 3mol C02, 2,7 mol H20 Bao toan nguyen to O tnr&c va sau phan ll'l1g

nH20

::) noz (can) = ncoz + -2- - 3. ny

= 3 + 1,35 - 0,6 = 3, 75 (mol).

ca.u 38: Chon D

Biroc 1: Chuyen de ve dang tong quat

mo!

co~- [

a mol tt+ - 0,1 mol C02

_ +

13a

mo! HC0³ 6 ^mol^tt+-+0,45 mo! C0² Btr&c 2: Ve hlnh

+

Hinh tong quat; Vl 0,1 mot < 0,45 mol ::) C6 2 truong hop xay ra:

THl:

TH2:

Your dreams-Our mission B{i

de

tinh tuy on thi THPT quoc gia mon H6a

LOVEBOOK.VN I 72

Anot(+): 2H20~02 +4W +4e 2. Tlnh chat h6a hoc cua cacbohidrat, peptit va protein.

An mon

di~n h6a, h6a hoc

4. Khi cho han hop kim loai tac dung VO'i

hon

hop IDUOi thi SU' dung

day

di~n hoa Va Ca.C dfr ki~n bat cho

de

^{tim ra}

san

phdm sau phan img,

B.BAIT!}>

1. each tinh ti I~ m~t xich trong polime

2. Chu y den

dang bat ~p thuy phan

ca

disaccarit

va

polisaccarit thi dua thro

PTHH de lam.

Boi

voi cac bai t~p di~n phan dung dich ta thuong SU' dung Bieu thtrc Faraday va dinh lu?t bao toan e.

4. Boi v&i bai tjp cho mu6i cua kim loai Al tac dung v&i dung dich kiem, nho th(r

n.r

xay ra phan frng:

Al3+

+

30H- --), Al(OH)3 ! (1) AI3+

+

40W _, Al0

2

⁽²⁾

5. Bai tj.p ve phan trng nhet nhom ta SU' dt;mg phuong trinh va phuong phap bao roan nguyen to O 6. f)oi v&i cac bai ~p ve peptit neu peptit gom cac a-amino axit no, mach h& trong phan ti'r chrra 1 nh6m -NH2,-COOH tao thanh k peptit thl d~t cong thrrc chung

la

C1em.Hz1cm+Z=kNkOk+t • Ngoai ra cac em c6 the tham khao them phuong phap

dong dang

h6a de dira cac peptit

ve

cac pha,n don giari hon,

'lilng,.,,, lcleil tlu1c Ii tlwyei vi Phlrllll/l phdp c,6 ll'olfll. tlA

ALYTHUYfr

1. f>i~n phan dung dich Catot(-): 2H20+2e 4H2 +20W

Dung djch muoi cua Dung dich mudi cua Zn Dung dlch mudi cua Dung dich muoi cua Al203

Al ZnO

Al - Phan (mg Phan (mg -

Zn - -

- -

Ba Mg Fe Al Ae.. Zn ZnO Mi:?0 Al,03 CuO

H2S04 BaS04 Hz r ^H2r Hz

r

Khong H21 Tan Tan Tan Tan

! tan (khong (khong (khong (dung

va.Hz mau) mau) mau) dich

r xanh)

Ba(OH)2 .f. trang .f. trang ! keo !keo ! keo !tclng J.keo

xanh trang trang trang trang

C:Su18:ChQnD

Ban clau cho cac chat tac dung v6i dung dlch H2S04•

Tao dung dich thudc thtr Ba(OH}ibang each cho du Ba vao dung dich H2S04loang.

Sau d6 cho dung dich Ba(OHh tac dung v6i cac dung dich san pham ben tren, 3600

+ IlgJucoza

=

~%. ny

= ax+ 2by

=

36 ₆₁^(ax+^by+^a+^b)(4)

[

a + b

=

0,4 (1) Tu- (l) (Z) (3) (4) =:> 4ax + 2by + 2b

=

1,14

' ' ' ax+ by + b = 0,51 . 25ax + 86by

=

36(a + b)(4) Thay (l)vao (4) => 25ax

+

86by

=

36.0,4

=

14,4 (5) Tu (2), (3), (5) :::) ax= 0,06; by

=

^0,15^va^b⁼^0,3

=> a = 0,4 - 0,3

=

0,1

a 0,1

~ %msaccarozo

=

^a+^{b ' 100%}

=

0,4, 100% = 25%

+) Phan (mg trang girong:

NH3

1 FructOZCY----+ 1 G!UCOZO'--+ 2 Ag

ax mol --+ 2ax mol

1 Glucozo- --+ 2 Ag

(ax+ 2by) mol--+ 2(ax + Zby) mol 1 MantOZ(Y --+ 2 Ag

(b- by) mol --+ 2(b - by) mol

~ nAg = 4ax + 2by + 2b = 1,14 mol (2) +) Phan Cmgv&i Br2:

1 Glucozo + 1 Br2 1 Mantozo + 1 Br2

(ax+ 2by) ~ (ax+ 2by) (b - by) --+ (b - by)

=:. nsri = ax+ by+ b = 0,51 mol (3)

Your dreams - Our mission BQ de tinh tuy on thi THPT quoc gla mon Hoa

9es6 8

Cau 1: Crng

vot

cong

thuc phan hr C4fl11N,

c9

x dong phan amin b~c nhat, y dong phan amin b~c hai va z dong phan a min b~c ba. Cac gia tr] x, y va z Ian Iuot bang:

A 4, 3 va 1 B. 4, 2 va 1 C. 3, 3 va O D. 3, 2

va

Cau 2: Day muoi nitrat nao trong 4 day rnudi duoi day khi bi dun n6ng phan

huy

tao ra cac san pham gorn oxitkim loai

+

N02

+

02?

A Al(NQ3)3, Zn(N03)z. Ba(N03)2. B. KN03, NaN03, LiN03.

C.

Mg(N03)2, Pb(N03)2., Fe(N03)2.

D.

Hg(N03)2, Mn(N03)2. AgN03.

CAu 3: Nh6m cacboxyl va nh6m amin trong proptein

lien ket

voi nhau bang

lien

ket ion. B.

lien

ket peptit. C.

lien

ket hidro. D.

lien

ket

amin.

CAu 4: Khi cho dung dich Na2C03 du vao dung dich chira ion Ba2+ ,Al:», Fe3+, N03 - thl ket tu.a thu duoc gom:

A BaC03,Fe(OH)3 ,Al(OH)3 B. BaC03,Al(OHt C.

Fe(OH)

³,Al(OH)3

D.

BaC03,Fe(OH)3

C~u 5: Nhfrng kim loai nao sau day dtrc;rc dieu

che

theo phirong phap nhiet luyen ?

A.

Al,Cu B. Ca,Cu C. Mg,Fe D. Fe,Ni

Cau 6: Hoa tan hoan toan l,18g hon hop X gom Alva Cu trong dung dich HCI thu dU'Q'C 0,672 I khi (dktc).

Phan tram ve khoi hrong Cu trong X la ?

A.

45,76% B.1% C. 54,24% D. 75,46%

Cdu 7:

Crom khong phan

img

v6i chat nao sau day?

A dung dich H2S04 loang dun nong B. dung dich NaOH Ioang,

C.

dung dich HN03 d~c, dun n6ng D. dung dich H2S04 d~c, dun n6ng

Cau 8: Chat nao sau day vira phan ll'ng duoc v&i dungdich HCl vira tac dung duoc v&i dung dich NaOH loang ?

A.

CrCl3 B. Cr(OH)3 C. Na2Cr04 D. NaCr02

Cdu 9:

Phat bieu nao sau day dung?

ATrong moi tnrong

kiem,

dipeptit mach h&

tac

dung duce v&i Cu(OH)Z cho dung dich mau tfrn xanh.

B.Trong met phan tu' tripeptit rnach ha

co

lien

ket peptit

C.Cac

hop chat peptit

ben

trong mdi tnrong bazo va

moi

truong axit.

D.axit glutarnic HOOC-CHz-CHrCH(NH2)-COOH c6 tfnh

hrong

tfnh.

Cau 10: Cho cac chat: gluCOZO', saccarozo, fructozo,

xenlulozo,

tinh bc)t

So

chat trong day khong tham gia phan img thiiy phan la?

A 3 B. 1 C. 2 D. 4

CAu 11:

Be

khir mui tanh cua ca, nguoi ta thuong dung gi?

A Giam B. Muoi C. Nuoc

da

D. Nu&c voi

Cau 12: Kim Ioai c6

nhi~t

dQ n6ng chay cao nhat dung

de lam

^dayt6c

bong den

la:

AW B. Au C. Pt D. Cr

CAu 13: Cac chat

X, Y, Z

c6

cung CTPT C2Hs02N. X

tac

dung duce

ca

v&i HCl va Na20. Y

tac

dung duce vot H moi sinh tao ra Y 1. Y 1 tac dung v&i H2S04 tao ra mudi Y 2. Y2

tac

dung v&i Na OH tai tao lai Y 1. Z

tac

dung v&i NaOH tao ra m9t mudi va khf NH3. CTCT dung cua X, Y, Z la:

AX (HCOOCH2NH2), Y(CH3COONH4), Z(CH2NH2COOH) B. X(CH3COONH4), Y(HCOOCH2NH2), Z(CH2NH2COOH) C. X(CH3 COONH4), Y(CH2NH2COOH), Z(HCOOCH2NH2)

D. X(CH2NH2COOH), Y(CH3CH2N02), Z(CH3COONH4)

C§.u 14:

Len

men dung dich chira 400g glucozo thu dm;rc 92g ancol etylic. Hi~u

suat qua

trlnh len men tao thanh ancol etylic

la:

A 30% B. 90% C. 45% D. 60%

Ciu 15: Dern phdn tich 0,005 mol m?,t este A thu dtr(_)'C 0,66 gam C02 va 0,27 garn H20. Biet ti khoi cua A doi v6i khong khf la 2,55. Khi cho A tac dung v&i NaOH cho m9t muoi ma khoi luong bang 34/37 khoi hrong A.

Cong thtrc don gian, cong thrrc phan tir, cong thirc

cau

tao ctia A

Ian

^hrc;rt

^Ia ^.

A C3H602, C3H602, HCOOC2Hs. B. C2H.,.02, C2H402l HCOO(H3 C. CH20, C2H102, HCOOCH3.

Your dreams- Our mission .. . :,. BQ de tinh tuy on thi THPT quot gia mon Hoa

LOVEBOOK.VN I 74

B.4,Qgam

va

^16,Qgam

CAu

23: Nung n6ng 100 gam

hon hop gom

Na2C03

va

NaHC03 cha den khi khoi

hrong

khfmg doi, dem

can

chat

ran

thu dtrQ'C thi

thay

n~ng

69g. Thanh

phan phan

tram

khoi hrong

cua m5i

chat trong h6n

hop

la?

A 16% Na2C03

va

84% NaHC03 B. 68% Na2C03 va 32% NaHC03 C. 84% Na2C03 va 16% NaHC03 D. 50% Na2C03 va 50% NaHC03

C;iu 24: Cho cac hop kim sau: Al- Zn (1); Fe- Zn (2); Zn- Cu (3); Mg- Zn (4). Khi

tiep

xuc v&i dung dich axit H2S04 loang

thl

cac

hQ'P

kim

ma

trong d6 Zn

bi an man

di~n h6a hoc tnroc

la

A (1), (2) va (3). B. (3)

va

(4).

c.

(2), (3)

Va

(4). D. (2) va (3).

CAu 25: Phat bieu sai

la

A.

Khi cho dung dich axit nitric d~c vao

dung

dich

long

trang tnmg

thay

c6 ket

tua

mau tim

xuat

hien.

Trong tài liệu Bộ đề tinh túy ôn thi THPT Quốc gia môn Hóa năm 2022 có lời giải chi tiết (Trang 65-68)

Des66

O. u 40: Chon D

=

+

+

= ~::)

=

T-x

lx =

+

=

=

to

the

+

=

=

+

+

=

=

co~- [

_ +

+

de

An mon

hon

day

de

san

2. Chu y den

ca

va

PTHH de lam.

Boi

n.r

+

+

2

la

dong dang

ve

'lilng,.,,, lcleil tlu1c Ii tlwyei vi Phlrllll/l phdp c,6 ll'olfll. tlA

ALYTHUYfr

- -

r

=

=

=

=

=

+

=

=

=

=

=

=

9es6 8

Cau 1: Crng

cong

c9

va

huy

+

+

C.

D.

lien ket

lien

lien

lien

lien

amin.

Fe(OH)

D.

che

A.

A.

^lx ⁼

^Ia ^.